document.write( "Question 370236: The speed of the boat in still water is 28 mph. the boat traveled 70 miles per hour downstream in the same amount of time that it took to travel 42 miles upstream. What is the rate of current of the river? \n" ); document.write( "
Algebra.Com's Answer #263893 by mananth(16946) You can put this solution on YOUR website! The speed of the boat in still water is 28 mph. the boat traveled 70 miles per hour downstream in the same amount of time that it took to travel 42 miles upstream. What is the rate of current of the river? \n" ); document.write( ".. \n" ); document.write( "let rate of current be x mph \n" ); document.write( "rate of boat in still water = 28mph \n" ); document.write( ".. \n" ); document.write( "Upstream rate = 28-x mph \n" ); document.write( "downstream rate = 28+x \n" ); document.write( ".. \n" ); document.write( "upstream distance = 42 miles \n" ); document.write( "downstream distance = 70 miles \n" ); document.write( "... \n" ); document.write( "t= d/r \n" ); document.write( "upstream time = downstream time \n" ); document.write( "... \n" ); document.write( "42/(28-x) = 70/x \n" ); document.write( "42x=70(28-x) \n" ); document.write( "42x=1960-70x \n" ); document.write( "42x+70x=1960 \n" ); document.write( "112x=1960 \n" ); document.write( "/112 \n" ); document.write( "x= 1960/112 \n" ); document.write( "x= 17.5 mph. the rate of current \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |