document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370172>Question 370172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of 30% HCl and 45% HCl would be needed to mix and produce 50 liters of 35% HCl?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #263824 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=263824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much of 30% HCl and 45% HCl would be needed <BR>\n" );
document.write( "to mix and produce 50 liters of 35% HCl?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "HCL + HCL = HCL<BR>\n" );
document.write( "0.30x + 0.45(50-x) = 0.35*50<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "30x + 45*50 - 45x = 35*50<BR>\n" );
document.write( "-15x = -10*50<BR>\n" );
document.write( "x = (2/3)50<BR>\n" );
document.write( "x = 33 1/3 liters (amt. of 30% solution needed in the mixture)<BR>\n" );
document.write( "50-x = 16 2/3 liters (amt. of 45% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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