document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370119>Question 370119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 52 inches squared. Its area is 153 inches squared. What is its length and width?\r<BR>\n" );
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document.write( "What I've done so far y=26-x <BR>\n" );
document.write( "-x^2+ 26x -52 = 0 \r<BR>\n" );
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document.write( "I get stuck while using the quadratic formula to use numbers to substitute into the next equation... Your help would greatly be appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #263774 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=263774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 52 inches squared. Its area is 153 inches squared. What is its length and width?\r<BR>\n" );
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document.write( "What I've done so far y=26-x <BR>\n" );
document.write( "-x^2+ 26x -52 = 0 <BR>\n" );
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document.write( "x + y = 26<BR>\n" );
document.write( "x*y = 153<BR>\n" );
document.write( "x*(26 - x) = 153 (you had 52)<BR>\n" );
document.write( "x^2 - 26x + 153 = 0<BR>\n" );
document.write( "(x-9)*(x-17) = 0<BR>\n" );
document.write( "x = 9, 17<BR>\n" );
document.write( "--> 9 by 17 inches\r<BR>\n" );
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