document.write( "Question 369422: A=A0(1.0177)^13*t what is the annual growth factor? \n" ); document.write( "
Algebra.Com's Answer #263763 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You don't say what unit of time is used for \"t\". This makes it difficult to answer the question. \n" ); document.write( "Assuming that t is measured in years... \n" ); document.write( "First we can use a rule for exponents, \n" ); document.write( " \n" ); document.write( "Next, we can raise 1.0177 to the thirteenth power (with a calculator): \n" ); document.write( " \n" ); document.write( "With the equation in this form, and assuming that \"t\" is in years, we can \"read\" the annual growth factor: 1.2561950239084477 (or \n" ); document.write( "Assuming that t is measured in days... \n" ); document.write( "If t is measured in days, then the number of years in \"t\" days would be t/365. This means we want to see t/365 in the exponent. It takes a little creative Algebra to rewrite your equation with t/365 in the exponent. First we multiply the exponent by 365/365. This is just a one and multiplying by 1 does not change whatever you are multiplying it by: \n" ); document.write( " \n" ); document.write( "Multiplying we get: \n" ); document.write( " \n" ); document.write( "which can be rewritten as: \n" ); document.write( " \n" ); document.write( "Using the rule for exponents as we did before: \n" ); document.write( " \n" ); document.write( "This makes the annual growth rate \n" ); document.write( "etc. for other measures of \"t\" \n" ); document.write( " |