document.write( "Question 370037: a tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. if the tortoise walks the first part and crawls the second, it takes 110 seconds. If it crawls the first part and walks the second, it takes 100 seconds. find the lengths of the two parts of the journey. \n" ); document.write( "
Algebra.Com's Answer #263684 by mananth(16946)\"\" \"About 
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let it walk x cm
\n" ); document.write( "let it crawl y cm
\n" ); document.write( "..
\n" ); document.write( "x/4 + y/3 = 110
\n" ); document.write( "3x+4y /12= 110
\n" ); document.write( "3x+4y = 1320.....................1
\n" ); document.write( "...
\n" ); document.write( "x/3 + y/4 = 100
\n" ); document.write( "4x+3y / 12 = 100
\n" ); document.write( "4x+3y= 1200......................2
\n" ); document.write( "...
\n" ); document.write( "multiply equation 1 by -4 & equation 2 by 3
\n" ); document.write( "-12x-16y= -5280
\n" ); document.write( "12x+9y = 3600
\n" ); document.write( "...
\n" ); document.write( "add the two equations
\n" ); document.write( "...
\n" ); document.write( "-7 y = -5280+3600
\n" ); document.write( "-7y = -1680
\n" ); document.write( "y = -1680/-7
\n" ); document.write( "y = 240 cm crawl
\n" ); document.write( "plug value of y in equation 1
\n" ); document.write( "3x+4y=12*110
\n" ); document.write( "3x+960=1320
\n" ); document.write( "3x=1320-960
\n" ); document.write( "3x=360
\n" ); document.write( "x = 120 cm walking \r
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\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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