document.write( "Question 369900: there are five people standing in a room. Antonio is 5 time the age of Patrick who is half the age of Merlyn. Ed is 30 years younger than double Merlyn and Patrick's combined ages. Precious is 79 years younger than Antonio. The sum of their ages is 271. How old is Precious? \n" ); document.write( "
Algebra.Com's Answer #263674 by mananth(16946)![]() ![]() You can put this solution on YOUR website! there are five people standing in a room. Antonio is 5 time the age of Patrick who is half the age of Merlyn. Ed is 30 years younger than double Merlyn and Patrick's combined ages. Precious is 79 years younger than Antonio. The sum of their ages is 271. How old is Precious? \n" ); document.write( ".. \n" ); document.write( "let Antonio = x years \n" ); document.write( "Precious = x-79 \n" ); document.write( "Antonio = x= 5* age of patrick \n" ); document.write( "Patrick = x/5 \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "Patrick = 1/2 age of Merlyn \n" ); document.write( "2*patrick = Merlyn \n" ); document.write( "2x/5= Merlyn \n" ); document.write( ".. \n" ); document.write( "Ed = 2*(2x/5 + x/5)-30 \n" ); document.write( "Ed = 2*(3x/5)-30 \n" ); document.write( "Ed= 6x/5-30\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "now you have all their ages in variables \n" ); document.write( "add them up \n" ); document.write( "x+x-79+x/5 +2x/5 +6x/5-30 =271 \n" ); document.write( "2x+x/5 +2x/5+6x/5 = 271+79+30 \n" ); document.write( "(10x+x+2x+6x)/5 =380 \n" ); document.write( "19x=5*380 \n" ); document.write( "x= 5*380/19 \n" ); document.write( "x = 100 Antonio's age \n" ); document.write( "Precious = Antonio's age -79 \n" ); document.write( ".. \n" ); document.write( "100-79 = 21 \n" ); document.write( "Precious is 21 years \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |