document.write( "Question 369984: The length of a room exceeds the width by 5 feet, and the height is 3 feet less than the width. The area of the four walls exceeds the sum fo the areas of ceiling and floor by 240 square feet. Find the dimensions of the room. \n" ); document.write( "
Algebra.Com's Answer #263663 by mananth(16946)\"\" \"About 
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let width be x
\n" ); document.write( "length = x+5
\n" ); document.write( "height = x-3
\n" ); document.write( "..
\n" ); document.write( "Area of 4 walls = 2*LH + 2*WH
\n" ); document.write( "= 2*(x-3)(x+5)+2*x*(x-3)
\n" ); document.write( "=2(x^2+2x-15)+2x^2-6x
\n" ); document.write( "=2x^2+4x-30+2x^2-6x
\n" ); document.write( "=4x^2-2x-30
\n" ); document.write( "...
\n" ); document.write( "Area of ceiling & floor
\n" ); document.write( "Area = 2 * LW
\n" ); document.write( "Area = 2*x*(x+5)
\n" ); document.write( "Area = 2x^2+10x
\n" ); document.write( "..
\n" ); document.write( "4x^2-2x-30 =2x^2+10x+240
\n" ); document.write( "2x^2-12x-270=0
\n" ); document.write( "/2
\n" ); document.write( "x^2-6x-135=0
\n" ); document.write( "x^2-15x+9x-135=0
\n" ); document.write( "x(x-15)+9(x-15)=0
\n" ); document.write( "(x-15)(x+9)=0
\n" ); document.write( "x= 15 feet the width
\n" ); document.write( "length = x+5 = 15 +5 = 20 feet
\n" ); document.write( "height = x-3 = 15-3 = 12 feet
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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