document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=370005>Question 370005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a race to a point 3miles away and back. Person A goes 20 mph, Person B goes 16mph. Where do they meet (in feet).<BR>\n" );
document.write( "I figured that it took person A .15 hours to the turning point and the Person B had traveled 2.4 miles in that time.<BR>\n" );
document.write( "I don't know how to go the rest of the answer....! Help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #263659 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=263659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  race distance = 3 & back\r<BR>\n" );
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document.write( "A = 20 mph<BR>\n" );
document.write( "B= 16 mph<BR>\n" );
document.write( "..\r<BR>\n" );
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document.write( "A takes 3/20 hour to reach other end\r<BR>\n" );
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document.write( "..<BR>\n" );
document.write( "By then<BR>\n" );
document.write( "B has reached 16*3/20 miles<BR>\n" );
document.write( "=12/5 miles<BR>\n" );
document.write( "..<BR>\n" );
document.write( "at this point of time  they are 3-(12/5) miles apart facing each other.<BR>\n" );
document.write( "=3/5 miles.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Now they are running towards each other<BR>\n" );
document.write( "their speeds when added up is 36 mph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "distance = 3/5 miles<BR>\n" );
document.write( "speed = 36 mph<BR>\n" );
document.write( "..<BR>\n" );
document.write( "time they meet = (3/5) /36<BR>\n" );
document.write( "3/5 *1/36<BR>\n" );
document.write( "=3/180  hours.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "in 3/180 hours B will run ( d= rt)<BR>\n" );
document.write( "3/180 * 20 <BR>\n" );
document.write( "=1/3 mile<BR>\n" );
document.write( "...<BR>\n" );
document.write( "1/3 * 5280 = 1760 feet  from the returning end.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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