document.write( "Question 369951: Plane a traveled 1400km
\n" ); document.write( "Plane b traveled 1000km and 50km/h faster than plane a in 3 hours less time.
\n" ); document.write( "How fast were the plane going \n" ); document.write( "

Algebra.Com's Answer #263656 by robertb(5830) $\"\"$ $\"About$

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$\"1400%2Fa+-+1000%2F%28a%2B50%29+=+3\"$ , using the formula t = d/r for the two planes and subtracting their times.
\n" ); document.write( " $\"1400a%2B70000-1000a+=+3a%5E2%2B150a+\"$ ,
\n" ); document.write( " $\"400a%2B70000+=++3a%5E2%2B150a\"$ ,
\n" ); document.write( " $\"0+=+3a%5E2-250a-70000\"$ ,
\n" ); document.write( " $\"q+=+%283a%2B350%29%28a-200%29\"$ , so a = 200 km/hr, the rate of plane a.
\n" ); document.write( "250 km/hr, the rate of plane b.
\n" ); document.write( " \n" ); document.write( "

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