document.write( "Question 369905: how to solve: a jogger and cyclist started at the same point and traveled for 2 hours in opposite directions until they were 42 miles apart. The cyclist traveled 10 mph faster than the jogger. \n" ); document.write( "

Algebra.Com's Answer #263623 by robertb(5830) $\"\"$ $\"About$

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Let j = rate of the jogger. Then j+10 = rate of cyclist.
\n" ); document.write( "Then 2j + 2(j+10) = 42,
\n" ); document.write( "2j + 2j + 20 = 42,
\n" ); document.write( "4j = 42-20 = 22,
\n" ); document.write( "or j = 5.5 miles per hour, the rate of the jogger.
\n" ); document.write( "j + 10 = 15.5 miles per hour, the rate of the cyclist. \n" ); document.write( "

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