document.write( "Question 369977: y=x+8
\n" ); document.write( "x+y=2
\n" ); document.write( "use substitution to solve each system of equation
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Algebra.Com's Answer #263609 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=2\"
\n" ); document.write( "\"y=x%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B%28x%2B8%29=2\" Plug in \"y=x%2B8\" into the first equation. In other words, replace each \"y\" with \"x%2B8\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B8=2\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"2x=2-8\"Subtract 8 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2x=-6\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-6%29%2F%282%29\" Divide both sides by 2 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"x=-3\", we can plug this into \"y=x%2B8\" to find \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-3%29%2B8\" Substitute \"-3\" for each \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=5\" Add\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=-3\" and \"y=5\" which also looks like \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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