document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=369888>Question 369888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much less is the area of a rectangular field 60 by 40 meters than that of a square field with the same perimeter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #263556 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=263556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of rectangle = L*W<BR>\n" );
document.write( "60*40 = 2400 m^2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "perimeter = 2L+2W<BR>\n" );
document.write( "= 2*60+2*40<BR>\n" );
document.write( "= 200 meters<BR>\n" );
document.write( "...<BR>\n" );
document.write( "side of square = perimeter / 4<BR>\n" );
document.write( "200/4 = 50 meters<BR>\n" );
document.write( "..<BR>\n" );
document.write( "area of square = 50*50 = 2500 m^2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "2500-2400 = 100 m^2 is the difference. <BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );