document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40873>Question 40873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the standard equation (y-2)^2=16(x+4) determine which conic section it represents, and name the vertex. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26350 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since one variable is squared and the other isn't, you know right away that this is a parabola...<BR>\n" );
document.write( "(y-2)^2 = 16(x+4)  now let's continue and solve for x...<BR>\n" );
document.write( "(1/16)(y-2)^2 = x+4<BR>\n" );
document.write( "x = (1/16)(y - 2)^2 - 4<BR>\n" );
document.write( "vertex at (-4, 2)<BR>\n" );
document.write( "It is noticeably wider than usual and concave right... </SPAN>\n" );
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