document.write( "Question 40949: 2x^2+2xy+x+y \n" ); document.write( "
Algebra.Com's Answer #26349 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! This problem involves factoring by grouping terms together.\r \n" ); document.write( "\n" ); document.write( "The first step is to find two nice groups containing like terms so that we can factor out the GCF. Usually there will only be two groups of terms.\r \n" ); document.write( "\n" ); document.write( "Try placing parenthesis around the first two terms and the second two terms.\r \n" ); document.write( "\n" ); document.write( " (2x^2+2xy)+(x+y)\r \n" ); document.write( "\n" ); document.write( "Now, look for the GCF (greatest common factor) within each group. Sometimes you may have to switch terms within groups until they have a GFC.\r \n" ); document.write( "\n" ); document.write( "Next, factor out the GCF from each group.\r \n" ); document.write( "\n" ); document.write( "The first group (2x^2+2xy)has a GCF of \"2x\". So factor out the 2x. \n" ); document.write( "This will leave: \n" ); document.write( " (2x)(x+y) \r \n" ); document.write( "\n" ); document.write( "The second group (x+y) only has a GCF of \"1\". So factor out the 1. \n" ); document.write( "This will leave: \n" ); document.write( " (1)(x+y)\r \n" ); document.write( "\n" ); document.write( "Putting everything back together gives:\r \n" ); document.write( "\n" ); document.write( " (2x)(x+y)+ (1)(x+y)\r \n" ); document.write( "\n" ); document.write( "Now,again factor out the GCF from the entire expression. What does each term have in common? What is the GCF?\r \n" ); document.write( "\n" ); document.write( "The GCF is \"(x+y)\". So after factoring out (x+y), group the remaining terms together to get the final answer.\r \n" ); document.write( "\n" ); document.write( " (x+y)(2x+1)\r \n" ); document.write( "\n" ); document.write( "Check the answer by multiplying the factors using FOIL. \n" ); document.write( " (x+y)(2x+1)\r \n" ); document.write( "\n" ); document.write( " 2x^2 + x + 2xy + y\r \n" ); document.write( "\n" ); document.write( "Rearranging the terms:\r \n" ); document.write( "\n" ); document.write( " 2x^2 + 2xy + x + y takes you back to the original expression.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |