document.write( "Question 369724: Solve for x.\r
\n" ); document.write( "\n" ); document.write( "e^-3x+2=40
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Algebra.Com's Answer #263483 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Not sure whether you meant:
\n" ); document.write( "\"e%5E-3x%2B2=40\"
\n" ); document.write( "Or
\n" ); document.write( "\"e%5E%28-3x%2B2%29=40\"
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\n" ); document.write( "I'll assume the later:
\n" ); document.write( "\"e%5E%28-3x%2B2%29=40\"
\n" ); document.write( "take the ln of both sides to give:
\n" ); document.write( "\"-3x%2B2=ln%2840%29\"
\n" ); document.write( "\"-3x=ln%2840%29-2\"
\n" ); document.write( "\"x+=+%28ln%2840%29-2%29%2F%28-3%29\"
\n" ); document.write( "\"x+=+1.6889%2F%28-3%29\"
\n" ); document.write( "\"x+=+-0.563\"\r
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