document.write( "Question 369434: For the conditional:
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document.write( "“If a>3 then a>0”. Determine the truthness of its converse.
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Algebra.Com's Answer #263482 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! The converse is \"If a > 0, then a > 3\", which is false. Notice that if a=1 (which is greater than zero), it is NOT greater than 3. \n" ); document.write( " |