document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=369645>Question 369645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 82 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #263480 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=263480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x, x+2 & x+4 be the 3 integers.<BR>\n" );
document.write( "x+2(x+2)+3(x+4)=82<BR>\n" );
document.write( "x+2x+4+3x+12=82<BR>\n" );
document.write( "6x=82-4-12<BR>\n" );
document.write( "6x=66<BR>\n" );
document.write( "x=66/6<BR>\n" );
document.write( "x=11 ans. for the first innteger.<BR>\n" );
document.write( "11+2=13 ans. for the second integer.<BR>\n" );
document.write( "11+4=15 ans. for the third integer.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "11+2*13+3*15=82<BR>\n" );
document.write( "11+26+45=82<BR>\n" );
document.write( "82=82<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );