document.write( "Question 369672: The probability that a fisherman catches a tuna in any one trip is 0.15
\n" ); document.write( "What is the probability, (3 decimals) that he catches a tuna on:\r
\n" ); document.write( "\n" ); document.write( "At least one of three excursions? (The answer is .386, but how?)\r
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Algebra.Com's Answer #263420 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Look at all of the possible outcomes for 3 excursions-\"C\" is catches, \"D\" is doesn't catch.
\n" ); document.write( "There are \"2%5E3\" possible outcomes.
\n" ); document.write( "\"CCC\"
\n" ); document.write( "\"CCD\"
\n" ); document.write( "\"CDC\"
\n" ); document.write( "\"CDD\"
\n" ); document.write( "\"DCC\"
\n" ); document.write( "\"DCD\"
\n" ); document.write( "\"DDC\"
\n" ); document.write( "\"DDD\"
\n" ); document.write( "Only one outcomes has him not catching at least one, DDD
\n" ); document.write( "\"P%28D%29=1-0.15=0.85\"
\n" ); document.write( "\"P%28DDD%29=%280.85%29%280.85%29%280.85%29=0.614125\"
\n" ); document.write( "P(DDD)+P(at least 1 C)=\"1\"
\n" ); document.write( "P(at least 1 C)=\"1-P%28DDD%29\"
\n" ); document.write( "P(at least 1 C)=\"1-0.614125\"
\n" ); document.write( "P(at least 1 C)=\"highlight%280.385875%29\"
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