document.write( "Question 369593: FIND THE DOMAIN OF THE FUNCTION
\n" ); document.write( "f(x)= 4/ square root of x - 9\r
\n" ); document.write( "\n" ); document.write( "\"f(x) equals 4 divided by the square root of x - 9\"\r
\n" ); document.write( "\n" ); document.write( "The answer is x > 9.
\n" ); document.write( "But I keep getting the answer- x is greater than OR EQUAL to 9.\r
\n" ); document.write( "\n" ); document.write( "What am i doing wrong?? HELP PLEASE.
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Algebra.Com's Answer #263387 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The domain of the function is all the x values for which \"f%28x%29\" is defined.
\n" ); document.write( "The square root function is defined as long as the argument is not negative.
\n" ); document.write( "\"x-9%3E=0\"
\n" ); document.write( "\"x%3E=9\"
\n" ); document.write( "Division by zero is also undefined so the x value when the denominator equals zero is not in the domain.
\n" ); document.write( "\"x-9=0\"
\n" ); document.write( "\"x=9\"
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\n" ); document.write( "So both of those must hold: x must be greater than or equal to 9 and x cannot equal 9, so that leaves that \"x%3E9\"
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\n" ); document.write( "Domain:\"x%3E9\" or in interval notation, (\"9\",\"infinity\")
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\n" ); document.write( "\"graph%28300%2C300%2C-2%2C18%2C-10%2C10%2C0%2C4%2Fsqrt%28x-9%29%29\"
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