document.write( "Question 369560: The sum of twice one number and 3 times another is 41. If the second is subtracted from the first, the difference is 8. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #263357 by acalgebra(30)\"\" \"About 
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Let the first number be x and the second number be y, then:
\n" ); document.write( "\"2x%2B3y=41\" and \"x-y=8\"
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\n" ); document.write( "The easiest way to solve this is to multiply the second equation by 3:
\n" ); document.write( "\"3x-3y=24\"
\n" ); document.write( "Now, add the equations:
\n" ); document.write( "\"2x%2B3y%2B3x-3y=41%2B24\"
\n" ); document.write( "Combine like terms:
\n" ); document.write( "\"5x=65\"
\n" ); document.write( "Divide both sides by 5 to simplify:
\n" ); document.write( "\"x=13\"
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\n" ); document.write( "Now, substitute 13 for each x in one of the original equations. In this case, the second equation will be easier.
\n" ); document.write( "\"13-y=8\"
\n" ); document.write( "Add y to each side:
\n" ); document.write( "\"13=y%2B8\"
\n" ); document.write( "Subtract 8 from each side:
\n" ); document.write( "\"5=y\"
\n" ); document.write( "\"y=5\"
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\n" ); document.write( "So, \"x=13\" and \"y=5\".
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