document.write( "Question 369560: The sum of twice one number and 3 times another is 41. If the second is subtracted from the first, the difference is 8. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #263357 by acalgebra(30)![]() ![]() You can put this solution on YOUR website! Let the first number be x and the second number be y, then: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The easiest way to solve this is to multiply the second equation by 3: \n" ); document.write( " \n" ); document.write( "Now, add the equations: \n" ); document.write( " \n" ); document.write( "Combine like terms: \n" ); document.write( " \n" ); document.write( "Divide both sides by 5 to simplify: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now, substitute 13 for each x in one of the original equations. In this case, the second equation will be easier. \n" ); document.write( " \n" ); document.write( "Add y to each side: \n" ); document.write( " \n" ); document.write( "Subtract 8 from each side: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, |