document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40926>Question 40926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> iF x varies inversely as y^2 and x=3 when y=24, find x when y=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26333 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If x varies inversely as y^2, we write that relationship as<BR>\n" );
document.write( "x = k / y^2<BR>\n" );
document.write( "Now plug in the original data to find the k...<BR>\n" );
document.write( "3 = k / 24^2<BR>\n" );
document.write( "k = 3 * 576 = 1728<BR>\n" );
document.write( "Now rewrite the relationship, using this k and the new data to find x...<BR>\n" );
document.write( "x = 1728 / y^2<BR>\n" );
document.write( "x = 1728 / 6^2<BR>\n" );
document.write( "x = 1728 / 36<BR>\n" );
document.write( "x = 48 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );