document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=369466>Question 369466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ONE-SIXTH OF A DENTIST'S AGE 8 YEARS AGO EQUALS ONE-TENTH OF HIS AGE 8 YEARS HENCE. WHAT IS HIS AGE NOW?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #263276 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=263276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ONE-SIXTH OF A DENTIST'S AGE 8 YEARS AGO EQUALS ONE-TENTH OF HIS AGE 8 YEARS HENCE. WHAT IS HIS AGE NOW? \r<BR>\n" );
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document.write( "Let x = the age of the dentist now\r<BR>\n" );
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document.write( "(x-8)/6 = (x+8)/10\r<BR>\n" );
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document.write( "Cross multiply<BR>\n" );
document.write( "10(x-8) = 6(x+8)<BR>\n" );
document.write( "10x-80  = 6x + 48<BR>\n" );
document.write( "     4x = 128<BR>\n" );
document.write( "      x = 32\r<BR>\n" );
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document.write( "The age of dentist now is 32 years old. </SPAN>\n" );
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