document.write( "Question 369132: Simplify\r
\n" ); document.write( "\n" ); document.write( "1/a+b - 1/a-b divided by 1/a-b + 1/a+b
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Algebra.Com's Answer #263264 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"%281%2F%28a%2Bb%29+-+1%2F%28a-b%29%29%2F%281%2F%28a-b%29+%2B+1%2F%28a%2Bb%29%29\"
\n" ); document.write( "Because subtraction of fractions can cause many errors, I like to change them into additions of the opposite:
\n" ); document.write( "\"%281%2F%28a%2Bb%29+%2B+%28-1%29%2F%28a-b%29%29%2F%281%2F%28a-b%29+%2B+1%2F%28a%2Bb%29%29\"
\n" ); document.write( "There are several ways to simplify this expression. The way I like to do this is:
  1. Find the Lowest Common Denomintor (LCD) of all the \"little\" denominators.
  2. Multiply the numerator and denominator of the \"big\" fraction by the LCD found in step 1.

\n" ); document.write( "Let's see how this works on your problem.
\n" ); document.write( "1) Find the LCD of the \"little\" denominators. The \"little\" denominators are (a+b) and (a-b). The LCD of these two is simply their product: (a+b)(a-b)
\n" ); document.write( "2) Multiply the numerator and denominator of the \"big\" fraction by the LCD:
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\n" ); document.write( "In both the numerator and denominator we will need to use the Distributive Property to multiply:
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\n" ); document.write( "Now all the \"little\" denominators cancel out:
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\n" ); document.write( "leaving:
\n" ); document.write( "\"%281%2A%28a-b%29+%2B+%28-1%29%2A%28a%2Bb%29%29%2F%281%2A%28a%2Bb%29+%2B+1%2A%28a-b%29%29\"
\n" ); document.write( "which simplifies as follows:
\n" ); document.write( "\"%28a+-+b+%2B+%28-a%29+%2B+%28-b%29%29%2F%28a+%2B+b+%2B+a+-+b%29\"
\n" ); document.write( "\"%28-2b%29%2F%282a%29\"
\n" ); document.write( "The 2's cancel leaving
\n" ); document.write( "\"%28-b%29%2Fa\"
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