document.write( "Question 369361: Use the quadratic formula to solve the equation.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-5x=-9\"
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Algebra.Com's Answer #263172 by acalgebra(30)\"\" \"About 
You can put this solution on YOUR website!
First, put the equation in standard form: \"x%5E2-5x%2B9\"
\n" ); document.write( "Then, note a, b, and c: \"a=1\", \"b=-5\", and\"c=9\"
\n" ); document.write( "Now, put a, b, and c into the quadratic equation: \"x+=+%285+%2B-+sqrt%28+-5%5E2-4%2A1%2A9+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "Then, solve: \"x+=+%285+%2B-+sqrt%28+-5%5E2-4%2A1%2A9+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+5+%2B-+sqrt%28+25-36+%29%2F%282%29\"
\n" ); document.write( "\"x+=+5+%2B-+sqrt%28+-9+%29%2F%282%29\"
\n" ); document.write( "Because there is a square root of a negative number, there are no real number solutions.
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