document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=369352>Question 369352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you write the slope-intercept form 2y+3=-1/3(x-2) into standard form? Thank you for your time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #263153 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=263153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How would you write the slope-intercept form 2y+3=-1/3(x-2) into standard form?<BR>\n" );
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document.write( "That's not slope-int form.<BR>\n" );
document.write( "2y+3=-1/3(x-2) = -x/3 + 2/3<BR>\n" );
document.write( "2y = -x/3 - 7/3<BR>\n" );
document.write( "y = (-1/6)x - 7/6 is slope-int form.  Solve for y to get that.<BR>\n" );
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document.write( "y = (-1/6)x - 7/6<BR>\n" );
document.write( "6y = -x - 7<BR>\n" );
document.write( "x + 6y = -7 in standard form<BR>\n" );
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