document.write( "Question 369293: The length of a rectangle is 2 less than 3 times the width. If the perimeter is 68, what is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #263128 by acalgebra(30)![]() ![]() You can put this solution on YOUR website! ------ \n" ); document.write( "3w-2=l \n" ); document.write( " \n" ); document.write( "perimeter=2(l+w) \n" ); document.write( "2([3w-2]+w) \n" ); document.write( "2(3w-2+w) \n" ); document.write( "2(4w-2) \n" ); document.write( "8w-4 \n" ); document.write( " \n" ); document.write( "perimeter=68 \n" ); document.write( "8w-4=68 \n" ); document.write( "8w=72 \n" ); document.write( "w=9 \n" ); document.write( " \n" ); document.write( "3w-2=l \n" ); document.write( "3(9)-2=l \n" ); document.write( "27-2=l \n" ); document.write( "25=l \n" ); document.write( "l=25 \n" ); document.write( " \n" ); document.write( "So the length is 25. \n" ); document.write( " |