document.write( "Question 369293: The length of a rectangle is 2 less than 3 times the width. If the perimeter is 68, what is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #263128 by acalgebra(30)\"\" \"About 
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\n" ); document.write( "3w-2=l
\n" ); document.write( "
\n" ); document.write( "perimeter=2(l+w)
\n" ); document.write( "2([3w-2]+w)
\n" ); document.write( "2(3w-2+w)
\n" ); document.write( "2(4w-2)
\n" ); document.write( "8w-4
\n" ); document.write( "
\n" ); document.write( "perimeter=68
\n" ); document.write( "8w-4=68
\n" ); document.write( "8w=72
\n" ); document.write( "w=9
\n" ); document.write( "
\n" ); document.write( "3w-2=l
\n" ); document.write( "3(9)-2=l
\n" ); document.write( "27-2=l
\n" ); document.write( "25=l
\n" ); document.write( "l=25
\n" ); document.write( "
\n" ); document.write( "So the length is 25.
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