document.write( "Question 369255: Hi, I have to find the vertical and horizontal asymptotes, as well as the y-intercept for the following:\r
\n" ); document.write( "\n" ); document.write( "\"y=%281+%2B+2x%29%2F%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "If I'm not mistaken,\r
\n" ); document.write( "\n" ); document.write( "vertical asymptote = \"-2\"
\n" ); document.write( "horizontal asymptotes are \"-2\" and \"-1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "I calculated the y-intercept by plugging 0 in for x and got 1/2, but when I graph the equation it doesn't look like 1/2. I appreciate any help you can provide :)
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Algebra.Com's Answer #263116 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
find the vertical and horizontal asymptotes, as well as the y-intercept for the following:\r
\n" ); document.write( "\n" ); document.write( "y=(1 + 2x)/(x+2)\r
\n" ); document.write( "\n" ); document.write( "If I'm not mistaken,\r
\n" ); document.write( "\n" ); document.write( "vertical asymptote = \"-2\"
\n" ); document.write( "horizontal asymptote: y = 2x/x = 2
\n" ); document.write( "-------------------------------------------- \r
\n" ); document.write( "\n" ); document.write( "I calculated the y-intercept by plugging 0 in for x and got 1/2, but when I graph the equation it doesn't look like 1/2.
\n" ); document.write( "---
\n" ); document.write( "x-int: Solve [(1+2x)/(x+2)] = 0
\n" ); document.write( "True when 1+2x = 0
\n" ); document.write( "2x = -1
\n" ); document.write( "x = -1/2
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\n" ); document.write( "\"graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%281%2B2x%29%2F%28x%2B2%29%29\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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