document.write( "Question 369244: Graph the quadratic function f(x)=7(x+1)^2+4: state the ordeed pairs representing the x-intercept and y-intercept (if any) and the vertex or the parabola. \n" ); document.write( "
Algebra.Com's Answer #263111 by lefty4ever26(59)\"\" \"About 
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\"f%28x%29=7%28x%2B1%29%5E2%2B4\" I simplified it by FOILing the (x+1)^2 and multiplying 7 thru giving me\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=7x%5E2%2B14x%2B11\" The x-intercept occurs when f(x)=0.
\n" ); document.write( "\"0=7x%5E2%2B14x%2B11\" Using the determinate \"sqrt%28b%5E2-4ac%29\" plugging in 7,14,11 for a,b,c. you determine that There is no x intercept because you can't take the square root of a negative number.\r
\n" ); document.write( "\n" ); document.write( "The y intercept is found when x=0. So plug in 0 for any x.\r
\n" ); document.write( "\n" ); document.write( "\"7%280%29%5E2%2B14%280%29%2B11=11\" SO the y intercept is at (0,11)\r
\n" ); document.write( "\n" ); document.write( "To find the vertex take the derivative of f(x) to get
\n" ); document.write( "\"f%27%28x%29=14x%2B14\" set equal to 0 and solve for x.
\n" ); document.write( "\"0=14x%2B14\"
\n" ); document.write( "\"x=-1\" Solve f(-1)\r
\n" ); document.write( "\n" ); document.write( "\"f%28-1%29=7-14%2B11=4\" So your vertex is at (-1,4) which is illustrated in the following graph
\n" ); document.write( "\"graph%28300%2C200%2C-5%2C5%2C-1%2C15%2C7%28x%2B1%29%5E2%2B4%29\"
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