document.write( "Question 369163: Find 4 consecutive odd integers such that the sum of the first and fourth is 75 more than 3 times the third. \n" ); document.write( "

Algebra.Com's Answer #263081 by lefty4ever26(59) $\"\"$ $\"About$

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FIND 4 CONSECUTIVE ODD INTEGERS
\n" ); document.write( "The first integer is x, the second is x+2, the third is x+4, the fourth is x+6.\r
\n" ); document.write( "\n" ); document.write( "The sum of the first and fourth (x+(x+6))
\n" ); document.write( "=75 more than 3 times the third (75+3(x+4)\r
\n" ); document.write( "\n" ); document.write( "SO (x+x+6)=75+3(x+4) Solve for x.\r
\n" ); document.write( "\n" ); document.write( " $\"2x%2B6=3x%2B87\"$
\n" ); document.write( " $\"6=x%2B87\"$
\n" ); document.write( " $\"x=-81\"$ So plugging this value in for x in the formulas for each integer.
\n" ); document.write( "x=-81
\n" ); document.write( "x+2=(-81)+2=-79
\n" ); document.write( "x+4=(-81)+4=-77
\n" ); document.write( "x+6=(-81)+6=-75\r
\n" ); document.write( "\n" ); document.write( "So your 4 integers are -81, -79, -77, -75 \n" ); document.write( "

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