document.write( "Question 369171: The perimeter of a field is 500 feet. Its width (shorter side) is 32 feet less than half its length (longer side). What is its width? \n" ); document.write( "
Algebra.Com's Answer #263064 by robertb(5830) You can put this solution on YOUR website! P = 500 = 2l + 2w \n" ); document.write( "w = l/2 - 32. \n" ); document.write( " By direct substitution, 2l + 2(l/2 - 32) = 500. \n" ); document.write( "2l + l-64 =500, \n" ); document.write( "3l = 564, \n" ); document.write( "l = 188 feet, the length of the rectangle. \n" ); document.write( "w = 94 - 32 = 62 feet, the width of the rectangle. \n" ); document.write( " |