document.write( "Question 369108: how do I get the answer to: sqrt(12x^2) \n" ); document.write( "
Algebra.Com's Answer #263057 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2812%2Ax%5E2%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%284%2A3%2Ax%5E2%29\" Factor \"12\" into \"4%2A3\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%284%29%2Asqrt%283%29%2Asqrt%28x%5E2%29\" Break up the square root using the identity \"sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283%29%2Asqrt%28x%5E2%29\" Take the square root of \"4\" to get \"2\".\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%283%29%2Ax\" Take the square root of \"x%5E2\" to get \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2Asqrt%283%29\" Rearrange and multiply the terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%2812%2Ax%5E2%29\" simplifies to \"2x%2Asqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%2812%2Ax%5E2%29=2x%2Asqrt%283%29\" where every variable is non-negative.
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