document.write( "Question 369177: Three times one number minus a second is 8, and the sum of the numbers is 12. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #263055 by lefty4ever26(59)\"\" \"About 
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3 times one number (3x) minus a second (-y) is 8 (=8). SO 3x-y=8.
\n" ); document.write( "sum of numbers (x+y) is 12 (=12). SO x+y=12.
\n" ); document.write( "\"3x-y=8\"
\n" ); document.write( "\"x%2By=12\" Solve this equation for y to get \"y=12-x\" Then you will plug this new value of y into the first equation and solve for x.\r
\n" ); document.write( "\n" ); document.write( "\"3x-%2812-x%29=8\"
\n" ); document.write( "\"3x-12%2Bx=8\"
\n" ); document.write( "\"4x-12=8\"
\n" ); document.write( "\"4x=20\"
\n" ); document.write( "\"x=5\" Then plug this value for x back into one of the equations to find y.\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=12\"
\n" ); document.write( "\"%285%29%2By=12\"
\n" ); document.write( "\"y=7\"
\n" ); document.write( "So the two numbers are 5 and 7.
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