document.write( "Question 369027: I have 16^(3/2)=64 and i have to put it in log form. I got the answer as log(base16)64=3/2. But it does not check, what am i doing wrong? \n" ); document.write( "

Algebra.Com's Answer #262987 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
If you started with:
\n" ); document.write( " $\"+16%5E%283%2F2%29=64+\"$
\n" ); document.write( "taking log base 16 of both sides:
\n" ); document.write( " $\"+3%2F2+=+log%2816%2C64%29+\"$
\n" ); document.write( " $\"+3%2F2+=+log%2864%29%2Flog%2816%29+\"$
\n" ); document.write( "cross multiplying
\n" ); document.write( " $\"+3%2Alog%2816%29+=+2%2Alog%2864%29+\"$
\n" ); document.write( "...
\n" ); document.write( "easier way would be to:
\n" ); document.write( " $\"+16%5E%283%2F2%29=64+\"$
\n" ); document.write( " $\"+sqrt%2816%5E3%29=64+\"$
\n" ); document.write( " $\"+sqrt%2816%2A16%2A16%29=64+\"$
\n" ); document.write( " $\"+16%2Asqrt%2816%29=64+\"$
\n" ); document.write( " $\"+16%2Asqrt%284%2A4%29=64+\"$
\n" ); document.write( " $\"+16%2A4=64+\"$
\n" ); document.write( " $\"+64=64+\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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