document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=369006>Question 369006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of an equilateral triangle (regular 3-gon) with the given measurement.\r<BR>\n" );
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document.write( "9-inch perimeter\r<BR>\n" );
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document.write( "A = sq. in.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #262967 by </B><A HREF=/tutors/aboutme.mpl?userid=lefty4ever26><B>lefty4ever26(59)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lefty4ever26><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lefty4ever26><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=262967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An equilateral triangle means all the sides have the same length.  So if the perimeter is 9 you would divide it by 3 to get each sides length. <BR>\n" );
document.write( "So 9/3=3.\r<BR>\n" );
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document.write( "A of a triangle=(1/2)base*height\r<BR>\n" );
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document.write( "To find the height you would cut the triangle in half down the middle to get 2 right triangles.  You will need to solve one of them to get the Vertical side.  <BR>\n" );
document.write( "The formula <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  we are looking for a so we need to rearrange the problem to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2=c%5E2-b%5E2 ALIGN=MIDDLE  ALT=\"a%5E2=c%5E2-b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  c is the side of your triangle equal to 3.  b is the 1/2 of the other side of your triangle so (3/2) Plug into the formula and solve for a.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2=3%5E2-%283%2F2%29%5E2 ALIGN=MIDDLE  ALT=\"a%5E2=3%5E2-%283%2F2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2=27%2F4 ALIGN=MIDDLE  ALT=\"a%5E2=27%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > , take the square root of both sides to solve for a\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=%28sqrt%2827%29%29%2F2 ALIGN=MIDDLE  ALT=\"a=%28sqrt%2827%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a=height.  <BR>\n" );
document.write( "SO to find area<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%281%2F2%29%283%29%28sqrt%2827%29%29%2F2 ALIGN=MIDDLE  ALT=\"A=%281%2F2%29%283%29%28sqrt%2827%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=3%28sqrt%2827%29%29%2F4 ALIGN=MIDDLE  ALT=\"A=3%28sqrt%2827%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Simplified<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=9%28sqrt%283%29%29%2F4 ALIGN=MIDDLE  ALT=\"A=9%28sqrt%283%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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