document.write( "Question 368992: : Factor completely: \r
\n" ); document.write( "\n" ); document.write( "3w^2 + 27w + 54
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Algebra.Com's Answer #262957 by lefty4ever26(59)\"\" \"About 
You can put this solution on YOUR website!
First you factor out the number that all three have in common which in this case is 3. SO we get:\r
\n" ); document.write( "\n" ); document.write( "3(w^2+9w+18) \r
\n" ); document.write( "\n" ); document.write( "Then you need to find the two numbers that multiply together to equal 18 and add together to equal 9. That would be 6 and 3 because 6*3=18, 6+3=9
\n" ); document.write( "So we get:
\n" ); document.write( "3(w+6)(w+3) \r
\n" ); document.write( "\n" ); document.write( "This is fully factored. To check you answer you would use the FOIL method to multiply the (w+6)(w+3). Then you would multiply the 3 back into that answer.\r
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\n" ); document.write( "\n" ); document.write( "**UPDATED CHECK**\r
\n" ); document.write( "\n" ); document.write( "3(w+6)(w+3) FOIL is First Outside Inside Last
\n" ); document.write( "3(w^2+3w+6w+18)
\n" ); document.write( "3(w^2+9w+18) Then distribute the 3 through by multiplying
\n" ); document.write( "3w^2+27w+54
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