document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=368967>Question 368967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you find the value of \"x\" in these two equations?\r<BR>\n" );
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document.write( "2x+4=3x-2<BR>\n" );
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document.write( "4-2x=3x-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #262920 by </B><A HREF=/tutors/aboutme.mpl?userid=lefty4ever26><B>lefty4ever26(59)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lefty4ever26><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lefty4ever26><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=262920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+4=3x-2   Subtract 2x from both sides.<BR>\n" );
document.write( "4=x-2       Add 2 to both sides.<BR>\n" );
document.write( "6=x   So, x=6.\r<BR>\n" );
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document.write( "4-2x=3x-2   Add 2x to both sides.<BR>\n" );
document.write( "4=5x-2     Add 2 to both sides.<BR>\n" );
document.write( "6=5x     Divide both sides by 5.<BR>\n" );
document.write( "6/5 = x   So, x=6/5.\r<BR>\n" );
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document.write( "Basically, you are trying to get x by itself.  The rule is anything you do to one side you have to do to the other, whether it be adding or subtracting a number or multiplying or dividing a number.  <BR>\n" );
document.write( "Good Luck! </SPAN>\n" );
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