document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=368964>Question 368964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The adjacent sides of a rectangle differ by 5 feet.If the area of the rectangle is 84 square feet, what is the lenght of the smaller side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #262915 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=262915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the smaller side be x<BR>\n" );
document.write( "the larger side will be x+5<BR>\n" );
document.write( "Area = 84 ft^2<BR>\n" );
document.write( "x(x+5)=84<BR>\n" );
document.write( "x^2+5x=84<BR>\n" );
document.write( "x^2+5x-84 =0<BR>\n" );
document.write( "x^2+12x-7x-84=0<BR>\n" );
document.write( "x(x+12)-7(x+12)=0<BR>\n" );
document.write( "(x+12)(x-7)=0<BR>\n" );
document.write( "x = 7 the smaller length <BR>\n" );
document.write( "the larger length will be 12<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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