document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5126>Question 5126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve and show steps to answer\r<BR>\n" );
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document.write( "15/x- 15/x-2 = -2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2629 by </B><A HREF=/tutors/aboutme.mpl?userid=guapa><B>guapa(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=guapa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15/x - 15/(x-2)= -2 First we have to make a restriction to avoid division by 0.<BR>\n" );
document.write( "x cannot be 0 or 2.<BR>\n" );
document.write( "We nee to find the LCD to clear the equation of all fractions. In this case the LCD is x(x-2)<BR>\n" );
document.write( "So we get: 15(x-2)- 15x= -2x(x-2)<BR>\n" );
document.write( "15x-30-15x=-2x²+4x<BR>\n" );
document.write( "2x²-4x-30=0<BR>\n" );
document.write( "x²-2x-15=0<BR>\n" );
document.write( "x²-5x+3x-15=0<BR>\n" );
document.write( "x(x-5)+3(x-5)=0<BR>\n" );
document.write( "(x+3)(x-5)=0<BR>\n" );
document.write( "x+3=0, x=-3<BR>\n" );
document.write( "x-5=0, x=5<BR>\n" );
document.write( "The solution set is {-3,5}<BR>\n" );
document.write( "Both solutions are possible since we made the restriction of 0 and 2. </SPAN>\n" );
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