document.write( "Question 40903: I need help...here is my question and the start to my answer...please help\r
\n" ); document.write( "\n" ); document.write( "(Q) Two cars with new tires are driven at an average speed of 60 mph for a test drive of 2000 miles. The diameter of the wheels of one car is 15 inches. The diameter of the wheels of the other car is 16 inches. If the tires are equally durable and differ only by diameter, which car will probably need new tires first? Why? \r
\n" ); document.write( "\n" ); document.write( "(A) The formula for circumference is 2 * pi * radius ( or pi * diameter)
\n" ); document.write( "So the circumference for the 16 in tire would be 16*pi = 50.26
\n" ); document.write( "The circumference of the 16 in. tire is : 16 * pi = 50.26
\n" ); document.write( "In 2000 miles, the 16 in. tire has rotated 2000/50.26 = 39.79 times
\n" ); document.write( "So, the 16 in. tire has done more work.
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Algebra.Com's Answer #26289 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
2000 miles = x inches
\n" ); document.write( "126,720,000 inches
\n" ); document.write( "First car's tire:
\n" ); document.write( "\"C+=+2%28pi%29r\"
\n" ); document.write( "\"C+=+%28pi%2915\" is about 47.12
\n" ); document.write( "126,720,000/47.12 = about 2,689,303 rotations
\n" ); document.write( "Second car's tire:
\n" ); document.write( "\"C+=+2%28pi%29r\"
\n" ); document.write( "\"C+=+%28pi%2916\" is about 50.27
\n" ); document.write( "126,720,000/50.27 = about 2,520,787 rotations
\n" ); document.write( "The first car's tire rotates more, so there is probably more 'ware and tare'.
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