document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40900>Question 40900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tommy drove his fully-loaded moving van 270 miles to Oklahoma City. With his van empty, Tommy drove 15mi/hr faster and made the return trip in 1.5 hours less. find the speed going.<BR>\n" );
document.write( "____mph<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26288 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 270/X=270/(X+15)-1.5 OR 270/X=(270-1.5X-22.5)/(X+15) OR \r<BR>\n" );
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document.write( "270(X+15)=X(270-1.5X-22.5) OR 270X+4050=270X-1.5X~2-22.5X OR\r<BR>\n" );
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document.write( "4050=-1.5X~2-22.5X OR 1.5X+22.5X-4050=0 OR X+15-2700=0 OR\r<BR>\n" );
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document.write( "(X+60)(X-45)=0 OR X=45 MPH GOING. </SPAN>\n" );
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