document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=368909>Question 368909</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I understand how I arrived at the equation I just can't get my calculator to work. I'm not sure how to input it into my calculator but what I need to find is \r<BR>\n" );
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document.write( "log 81+ 2log 4<BR>\n" );
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document.write( "log 4-log 3\r<BR>\n" );
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document.write( "In words: Log eighty one plus two log four divided by log four minus log 3. <BR>\n" );
document.write( "I have to find the decimal approximation to the nearest thousandth. <BR>\n" );
document.write( "Thank You very much for your help. <BR>\n" );
document.write( "Erica<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #262857 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=262857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log^81+2log4-log(3)\r<BR>\n" );
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document.write( "To find an approximate value of log4, use the formula log^ng81=(ln(g81))/(ln(n)).<BR>\n" );
document.write( "g81lo+((2ln(4))/(ln(10)))-log(3)\r<BR>\n" );
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document.write( "Find the value of each expression using a calculator.<BR>\n" );
document.write( "g81lo+(20.60206)-log(3)\r<BR>\n" );
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document.write( "To find an approximate value of log(3), use the formula log^ng81=(ln(g81))/(ln(n)).<BR>\n" );
document.write( "g81lo+(20.60206)+(-(ln(3))/(ln(10)))\r<BR>\n" );
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document.write( "Find the value of each expression using a calculator.<BR>\n" );
document.write( "g81lo+(20.60206)+(-0.4771213)\r<BR>\n" );
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document.write( "Remove the parentheses that are not needed from the expression.<BR>\n" );
document.write( "g81lo+20.60206-0.4771213\r<BR>\n" );
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document.write( "Subtract 0.4771213 from 20.60206 to get 20.12494.<BR>\n" );
document.write( "g81lo+20.12494 </SPAN>\n" );
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