document.write( "Question 368875: a solution is 30% chlorine and another solution is 60% chlorine.how many liters of each solution should you use to make 120 liters of a solution that is 40% chlorine \n" ); document.write( "
Algebra.Com's Answer #262819 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 30% solution, B the amount of 60% solution.
\n" ); document.write( "1.\"A%2BB=120\"
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\n" ); document.write( "\"30A%2B60B=40%28120%29\"
\n" ); document.write( "2.\"A%2B2B=160\"
\n" ); document.write( "Subtract eq. 1 from eq. 2,
\n" ); document.write( "\"A%2B2B-A-B=160-120\"
\n" ); document.write( "\"highlight%28B=40%29\"liters
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\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"A%2B40=120\"
\n" ); document.write( "\"highlight%28A=80%29\"liters
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