document.write( "Question 368822: if it takes an airplane 3 hrs to fly 360 mi with the wind and 4 h to make the return trip against the wind find the speed of the wind and the air speed of the airplane. \n" ); document.write( "
Algebra.Com's Answer #262783 by mananth(16946) You can put this solution on YOUR website! let speed of plane in still air be x \n" ); document.write( "speed of wind be y \n" ); document.write( ".. \n" ); document.write( "speed with wind = x+y \n" ); document.write( "speed against wind = x-y \n" ); document.write( "... \n" ); document.write( "distance with wind =360 miles \n" ); document.write( "time = 3 hours \n" ); document.write( "d/r = t \n" ); document.write( "360/(x+y)=3 \n" ); document.write( "360 = 3x+3y \n" ); document.write( "/3 \n" ); document.write( "120=x+y......................1 \n" ); document.write( "... \n" ); document.write( "... \n" ); document.write( "Distance against wind = 360 miles \n" ); document.write( "time = 4 \n" ); document.write( "speed = x-y \n" ); document.write( "... \n" ); document.write( "360/(x-y)=4 \n" ); document.write( "/4 \n" ); document.write( "90/(x-y)=1 \n" ); document.write( "x-y = 90.................2 \n" ); document.write( "add 1 & 2 \n" ); document.write( "2x=210 \n" ); document.write( "/2 \n" ); document.write( "x= 105 mph speed of plane \n" ); document.write( "speed of wind = 120-105=15 mph.\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |