document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40807>Question 40807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cylindrical tin has an internal diameter of 18 cm. It contains water to a height of 13.2 cm. How far will the water level rise when a heavy ball 9.3 cm in diameter is immersed in it ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26275 by </B><A HREF=/tutors/aboutme.mpl?userid=astromathman><B>astromathman(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=astromathman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=astromathman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, note that it is clear that the ball will be completely submerged.  If this were not so, we would have to be more careful.  Since it IS so, the ball simply pushes up an equal volume of water, so we can add the volume of the ball to the volume of the water as though it were all water.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol%5BC%5D=A%5Bb%5Dh+=%28pi+%2Ar%5E2%29%2Ah ALIGN=MIDDLE  ALT=\"Vol%5BC%5D=A%5Bb%5Dh+=%28pi+%2Ar%5E2%29%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol%5BS%5D=%284%2F3%29%2A+pi+%2Ar%5E3 ALIGN=MIDDLE  ALT=\"Vol%5BS%5D=%284%2F3%29%2A+pi+%2Ar%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Using these, the ball has volume <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=421%28cm%5E3%29 ALIGN=MIDDLE  ALT=\"421%28cm%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the volume of the water in the can is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3359%28cm%5E3%29 ALIGN=MIDDLE  ALT=\"3359%28cm%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > for a total of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3780%28cm%5E3%29 ALIGN=MIDDLE  ALT=\"3780%28cm%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Setting <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi+%2A9%5E2%29%2Ah=3780 ALIGN=MIDDLE  ALT=\"%28pi+%2A9%5E2%29%2Ah=3780\"   DISABLED_style= \"max-width:90%; height:auto;\" > and solving for h yields <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=3780%2F%2881pi%29+=+14.85%2Acm ALIGN=MIDDLE  ALT=\"h=3780%2F%2881pi%29+=+14.85%2Acm\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "(Answers will vary slightly depending on whether you use your calculator's version of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > or type in 3.14.) </SPAN>\n" );
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