document.write( "Question 368793: Find three consecutive intergers such that the sum of twice the smallest and 3 times the largest is 126.
\n" ); document.write( "I've attempted, and i know the answer is 24, 25, and 26. i just dont know how to get the work, cause i need to know how to do the work so i can solve all the other problems later. \n" ); document.write( "
Algebra.Com's Answer #262725 by neatmath(302)\"\" \"About 
You can put this solution on YOUR website!
Let x be the first integer. The next two consecutive integers are x+1 and x+2, thus we are given:
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\n" ); document.write( "\n" ); document.write( "2*(x)+3*(x+2)=126
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\n" ); document.write( "\n" ); document.write( "2x+3x+6=126
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\n" ); document.write( "\n" ); document.write( "5x+6=126
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\n" ); document.write( "\n" ); document.write( "5x=120
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\n" ); document.write( "\n" ); document.write( "x=24
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\n" ); document.write( "\n" ); document.write( "Thus, the three consecutive integers are 24, 25, and 26, as you had suspected.
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\n" ); document.write( "\n" ); document.write( "I hope this helps!
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