document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40881>Question 40881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Harry has $4000 invested in 2 savings accounts. One account earns 6% interest per year, and the other pays 7% per year. If his total interest for the year is $264, how much is invested at 7%? (The answer is not $264 or $1600)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26272 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .06X+.07(4000-X)=264 OR .06X+280-.07X=264 OR -.01X=-16 OR X=1600 INVESTED @ 6%\r<BR>\n" );
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document.write( "THUS 4000-1600=2400 INVESTED @ 7%.\r<BR>\n" );
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document.write( "PROOF .06*1600+.07*2400=264 OR 96+168=264 OR 264=264 </SPAN>\n" );
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