document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5142>Question 5142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help\r<BR>\n" );
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document.write( "The length of a rectangle is 4 centimeters less than twice the width.  Find the dimensions of the rectangle if the area is 96 square centimeters. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2627 by </B><A HREF=/tutors/aboutme.mpl?userid=guapa><B>guapa(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=guapa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need the area formula for a rectangle. A = lw<BR>\n" );
document.write( "We have the value for the area which is 96<BR>\n" );
document.write( "The length is 4cm less than twice the width. Let w = width then l=2w-4<BR>\n" );
document.write( "Now we can substitue into the formula:<BR>\n" );
document.write( "96=(2w-4)w<BR>\n" );
document.write( "96=2w²-4w<BR>\n" );
document.write( "2w²-4w-96=0<BR>\n" );
document.write( "2w²-16w+12w-96=0<BR>\n" );
document.write( "2w(w-8)+12(w-8)=0<BR>\n" );
document.write( "(2w+12)(w-8)=0<BR>\n" );
document.write( "2w+12=0, w= -12/2= -6<BR>\n" );
document.write( "w-8=0, w=8<BR>\n" );
document.write( "Since we are looking for dimensions of a rectangle we can disgard the negative solution.<BR>\n" );
document.write( "w=8 and 2w-4=l , 2(8)-4=l, 12=l<BR>\n" );
document.write( "The dimension for the rectangle is 12 by 8 cm.<BR>\n" );
document.write( "Check it A=l*w = 12*8=96 </SPAN>\n" );
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