document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=368712>Question 368712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find S if r=2 inches and theta=12 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #262695 by </B><A HREF=/tutors/aboutme.mpl?userid=neatmath><B>neatmath(302)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=neatmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=neatmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=262695\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The arc length s is given by the radius times the angle theta, or <br>\r<BR>\n" );
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document.write( "s=r*theta<br>\r<BR>\n" );
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document.write( "But the key to this problem is that we need to know the measure of theta in RADIANS!<br>\r<BR>\n" );
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document.write( "So 12 degrees equals how many radians?<br>\r<BR>\n" );
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document.write( "12 degrees = [(pi/180)*12]radians or<br>\r<BR>\n" );
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document.write( "theta=pi/15 radians<br>\r<BR>\n" );
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document.write( "So, our arc length is given by<br>\r<BR>\n" );
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document.write( "s=r*theta<br>\r<BR>\n" );
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document.write( "s=2*(pi/15)<br>\r<BR>\n" );
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document.write( "<b>s=(2*pi)/15 inches </b><br>\r<BR>\n" );
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document.write( "which you can approximate using the value of 3.1415926... for pi.<br>\r<BR>\n" );
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document.write( "I hope this helps!<br> </SPAN>\n" );
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