document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40864>Question 40864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One machine in a print shop can produce a certain # of pages twice as fast as another machine. Operating together these machines can produce this number of pages in 8 minutes. How long would it take the slower machine working alone to produce this number of pages?<BR>\n" );
document.write( "______minutes.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26266 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2x*x)/(2x+x)=8 or 2x~2/3x=8 or 2x~2=24x or 2x~2-24x=0 or 2x(x-12)=0 or x=12 thus 2*12 or 24 min for the slower maching.\r<BR>\n" );
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document.write( "proof 2*12*12/(2*12+12)=8 or 288/36=8 or 8=8 </SPAN>\n" );
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