document.write( "Question 368460: Find the maximum or minimum of the function f(x)=8x^2-4x+50. \n" ); document.write( "

Algebra.Com's Answer #262569 by Fombitz(32388) $\"\"$ $\"About$

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\n" ); document.write( "Convert to vertex form, $\"y=a%28x-h%29%5E2%2Bk\"$ , by completing the square.
\n" ); document.write( " $\"f%28x%29=8x%5E2-4x%2B50\"$
\n" ); document.write( " $\"f%28x%29=8%28x%5E2-%281%2F2%29x%29%2B50\"$
\n" ); document.write( " $\"f%28x%29=8%28x%5E2-%281%2F2%29x%2B1%2F16%29%2B50-8%2F16\"$
\n" ); document.write( " $\"f%28x%29=8%28x-1%2F4%29%5E2%2B100%2F2-1%2F2\"$
\n" ); document.write( " $\"f%28x%29=8%28x-1%2F4%29%5E2%2B99%2F2\"$
\n" ); document.write( "The maximum/minimum occurs at the vertex.
\n" ); document.write( "Since $\"a=8%3E0\"$ , the parabola opens upwards and the vertex value is a minimum.
\n" ); document.write( " $\"y%5Bmin%5D=99%2F2\"$
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